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one method is to have:Y
9 8 7 6 5 9 8 7 6 5 maps to
甲乙丙丁戊己庚辛壬癸O/
and©緣生術數研究社 -- 術數研究 LO
9 8 7 6 5 4 9 8 7 6 5 4 maps toa
子丑寅卯辰巳午未 申酉 戌亥
then e.g. for~[(r(
甲子乙丑, add them together, gets 9+8+9+8 = 34.o2_
divided by 5, remainder is 4, and then, I forgot ... but it's documented in many books.hPt
©緣生術數研究社 -- 術數研究 T:]6,
the 2nd method is based on previous method, and using the "palm" to aid the calculation, and should be able to count the result within 2-5 seconds. It's quite hard for me to illustrate here though ... it's maths, anyway. not hard to derive oneself. This method is documented in 1 or 2 books only -- the books I have read so far.iO6#n
©緣生術數研究社 -- 術數研究 /t
But I have to admit that if you have good memory, 方法一 is a good way.X
©緣生術數研究社 -- 術數研究 F|vaHH
And finally, my suggestion is, to prepare a cheat-sheet ... or, save it in PDA...(NZZ
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2006/03/12 09:37am 
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