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one method is to have:ccq
9 8 7 6 5 9 8 7 6 5 maps to
甲乙丙丁戊己庚辛壬癸,6iiN
and©緣生術數研究社 -- 術數研究 v
9 8 7 6 5 4 9 8 7 6 5 4 maps toQAd{[\
子丑寅卯辰巳午未 申酉 戌亥
then e.g. forZ)?I
甲子乙丑, add them together, gets 9+8+9+8 = 34.t;\
divided by 5, remainder is 4, and then, I forgot ... but it's documented in many books.ft
©緣生術數研究社 -- 術數研究 |6',J)
the 2nd method is based on previous method, and using the "palm" to aid the calculation, and should be able to count the result within 2-5 seconds. It's quite hard for me to illustrate here though ... it's maths, anyway. not hard to derive oneself. This method is documented in 1 or 2 books only -- the books I have read so far.laj
©緣生術數研究社 -- 術數研究 7
But I have to admit that if you have good memory, 方法一 is a good way.f7|y
©緣生術數研究社 -- 術數研究 #
And finally, my suggestion is, to prepare a cheat-sheet ... or, save it in PDA...[;
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2006/03/12 09:37am 
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